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How many divisors does the number $N = 2^3 \times 3^2 \times 5$ have?
A$6$
B$12$
C$24$
D$30$
Answer & Solution
Correct answer: C. $24$
Number of divisors = product of (exponent + 1) for each prime. (3+1) × (2+1) × (1+1) = 4 × 3 × 2 = 24.
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