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If $P(A) = 0.5, P(B) = 0.4, P(A \cap B) = 0.2$, then $P(A | B)$ is:
A$0.4$, the value of $P(B)$ itself on the chart here
B$0.2$, the value of the joint event probability here
C$0.5$, since $P(A | B) = P(A \cap B)/P(B) = 0.2/0.4$
D$0.8$, the simple sum of $P(A) + P(A \cap B)$ here
Answer & Solution
Correct answer: C. $0.5$, since $P(A | B) = P(A \cap B)/P(B) = 0.2/0.4$
$P(A | B) = P(A \cap B)/P(B) = 0.2/0.4 = 0.5$.
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