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A fair coin is tossed twice. The probability of getting at least one head is:
A$1/4$, the chance of two heads on the school chart only
B$3/4$, since $P(\geq 1H) = 1 - P(TT) = 1 - 1/4 = 3/4$
C$1/2$, the probability of one head and one tail on chart
D$1$, since at least one head is always certain on chart
Answer & Solution
Correct answer: B. $3/4$, since $P(\geq 1H) = 1 - P(TT) = 1 - 1/4 = 3/4$
$P(\text{no head}) = 1/4$; $P(\geq 1H) = 1 - 1/4 = 3/4$.
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