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The determinant of $\begin{pmatrix}3 & 2 \\ 1 & 4\end{pmatrix}$ is:
A$10$, the sum of all entries of the matrix on the chart
B$5$, half the average of all entries on the chart here
C$10$, since $\det = 3\cdot 4 - 2\cdot 1 = 12 - 2 = 10$
D$14$, summing diagonal product without subtracting here
Answer & Solution
Correct answer: C. $10$, since $\det = 3\cdot 4 - 2\cdot 1 = 12 - 2 = 10$
$\det = ad - bc = 3\cdot 4 - 2\cdot 1 = 10$.
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