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A $0.5$ molal aqueous solution of a non-electrolyte ($K_b = 0.52$ K kg/mol for water) boils at:
A$100.26^\circ$C, with $\Delta T_b = K_b m = 0.52\cdot 0.5$
B$99.74^\circ$C, lowering instead of raising the boil point
C$100^\circ$C, since dilute solutions boil at the pure value
D$101^\circ$C, doubling the molal elevation constant value
Answer & Solution
Correct answer: A. $100.26^\circ$C, with $\Delta T_b = K_b m = 0.52\cdot 0.5$
$\Delta T_b = K_b m = 0.52\cdot 0.5 = 0.26$ K; bp = $100.26^\circ$C.
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