Home › CBSE Class 11 › Chemistry › Chemical Equilibrium › For the reaction $N_2 + 3H_2 \rightleftharpoons …
For the reaction $N_2 + 3H_2 \rightleftharpoons 2NH_3$, the equilibrium constant is:
A$K = [NH_3]/([N_2][H_2])$, with no exponents in formula
B$K = [NH_3]^2/([N_2][H_2]^3)$, using stoichiometric powers
C$K = [N_2][H_2]^3/[NH_3]^2$, the inverse of the correct expression
D$K = [NH_3]^2 - [N_2][H_2]^3$, a difference instead of ratio
Answer & Solution
Correct answer: B. $K = [NH_3]^2/([N_2][H_2]^3)$, using stoichiometric powers
$K_c = [NH_3]^2/([N_2][H_2]^3)$ by stoichiometric powers.
Related questions
For Fe³⁺(aq) + SCN⁻(aq) ⇌ [Fe(SCN)]²⁺(aq), adding more KSCN causes the Fe³⁺ concentration The solubility of carbon dioxide in a soft drink falls as temperature rises because dissolWhen the temperature of an exothermic reaction at equilibrium is raised, the equilibrium cAdding a catalyst to a reversible reaction at equilibrium:A sealed flask of reacting gases shows no colour change for an hour. What is actually happBesides VSEPR and the Kossel Lewis approach, which two theories are listed?Which theory is abbreviated VSEPR?Why can lattice enthalpy not be calculated directly from attraction and repulsion alone?