For the reaction $N_2 + 3H_2 \rightleftharpoons 2NH_3$, the equilibrium constant is:
A$K = [NH_3]/([N_2][H_2])$, with no exponents in formula
B$K = [NH_3]^2/([N_2][H_2]^3)$, using stoichiometric powers
C$K = [N_2][H_2]^3/[NH_3]^2$, the inverse of the correct expression
D$K = [NH_3]^2 - [N_2][H_2]^3$, a difference instead of ratio
Answer & Solution
Correct answer: B. $K = [NH_3]^2/([N_2][H_2]^3)$, using stoichiometric powers
$K_c = [NH_3]^2/([N_2][H_2]^3)$ by stoichiometric powers.
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