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For a reaction occurring at constant pressure in an open beaker, the heat absorbed equals:
A$\Delta U$, the change in internal energy of the system here
B$\Delta H$, the change in enthalpy at constant pressure here
C$T\Delta S$, the temperature-times-entropy product directly
D$P\Delta V$, the work done against the atmosphere alone
Answer & Solution
Correct answer: B. $\Delta H$, the change in enthalpy at constant pressure here
At constant pressure, $q_p = \Delta H$.
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