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The molecular mass of water H$_2$O (using H = 1, O = 16) is:
A$17$ amu, summing H and O without doubling H here
B$18$ amu, by $2\cdot 1 + 16$ for two H plus one O
C$34$ amu, doubling the entire molecular mass shown
D$8$ amu, dividing the larger atomic mass alone
Answer & Solution
Correct answer: B. $18$ amu, by $2\cdot 1 + 16$ for two H plus one O
$H_2O = 2(1) + 16 = 18$ amu.