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Doubling the intensity of incident light on a metal plate above threshold frequency changes:
AThe maximum KE of photoelectrons, which now doubles
BThe threshold frequency, which falls to half the original value
CThe number of photoelectrons per second, which doubles too
DThe work function of the metal, halving with intensity rise
Answer & Solution
Correct answer: C. The number of photoelectrons per second, which doubles too
Intensity controls photon flux, hence number of photoelectrons. Max KE depends on frequency only.
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