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A long straight wire carries $5$ A. The magnetic field $0.10$ m away from the wire is:
A$1.0\times 10^{-5}$ T, by $B = \mu_0 I/(2\pi r)$
B$5\times 10^{-7}$ T, ignoring the $2\pi$ factor here
C$1.0$ T, ignoring all scaling on the formula
DZero, since the wire is straight, not coiled
Answer & Solution
Correct answer: A. $1.0\times 10^{-5}$ T, by $B = \mu_0 I/(2\pi r)$
$B = 4\pi\times 10^{-7}\cdot 5/(2\pi\cdot 0.1) = 1.0\times 10^{-5}$ T.
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