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An FM radio broadcasts at $92.7$ MHz. The wavelength of the carrier in air is approximately:
A$92.7$ m, the same number as the frequency value
B$0.927$ m, taking the frequency in kilohertz here
C$30$ m, ignoring the frequency entirely in the formula
D$3.24$ m, since $\lambda = c/f = 3\times 10^8/9.27\times 10^7$
Answer & Solution
Correct answer: D. $3.24$ m, since $\lambda = c/f = 3\times 10^8/9.27\times 10^7$
$\lambda = c/f = 3\times 10^8/9.27\times 10^7 \approx 3.24$ m.