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An ideal transformer with primary $1000$ turns and secondary $50$ turns is fed $230$ V AC. Secondary voltage is:
A$230$ V, since transformers do not change voltage
B$4600$ V, the inverse turns ratio applied here
C$50$ V, equal to the secondary turn count value
D$11.5$ V, since $V_s = V_p N_s/N_p = 230\cdot 50/1000$
Answer & Solution
Correct answer: D. $11.5$ V, since $V_s = V_p N_s/N_p = 230\cdot 50/1000$
$V_s = V_p\cdot N_s/N_p = 230\cdot 50/1000 = 11.5$ V.
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