Home › UP Board Class 12 › physics › Alternating Current › In a series LCR circuit, resonance occurs at ang…
In a series LCR circuit, resonance occurs at angular frequency:
A$\omega_0 = LC$, the product of the two component values
B$\omega_0 = R/(LC)$, including resistance in the formula
C$\omega_0 = 1/\sqrt{LC}$, when $X_L = X_C$ in the loop
D$\omega_0 = \sqrt{LC}$, the square root of the product
Answer & Solution
Correct answer: C. $\omega_0 = 1/\sqrt{LC}$, when $X_L = X_C$ in the loop
At resonance $X_L = X_C \Rightarrow \omega L = 1/(\omega C) \Rightarrow \omega = 1/\sqrt{LC}$.