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An inductor of $0.1$ H is connected to a $50$ Hz AC source. Its inductive reactance is:
A$31.4$ $\Omega$, by $X_L = \omega L = 2\pi\cdot 50\cdot 0.1$
B$5$ $\Omega$, the product of frequency and inductance only
C$0.1$ $\Omega$, equal to the inductance value alone
DZero, since inductors block DC, not AC mains
Answer & Solution
Correct answer: A. $31.4$ $\Omega$, by $X_L = \omega L = 2\pi\cdot 50\cdot 0.1$
$X_L = \omega L = 2\pi\cdot 50\cdot 0.1 \approx 31.4\ \Omega$.