Home › UP Board Class 12 › Physics › Electromagnetic Induction › A copper rod of length $0.5$ m slides at $4$ m/s…
A copper rod of length $0.5$ m slides at $4$ m/s perpendicular to a $0.2$ T field. The motional EMF is:
A$1$ V, ignoring one of the three factors in the formula
B$0.4$ V, by $\varepsilon = Bvl = 0.2\cdot 4\cdot 0.5$
C$2$ V, multiplying field by velocity by velocity here
DZero, since the rod is not connected to anything
Answer & Solution
Correct answer: B. $0.4$ V, by $\varepsilon = Bvl = 0.2\cdot 4\cdot 0.5$
$\varepsilon = Bvl = 0.2\cdot 4\cdot 0.5 = 0.4$ V.
Related questions
The coil of an AC generator connects to the outside circuit through:A coil is labelled 2 H. The H stands for the unit called the:A magnet dropped through an aluminium pipe, compared with a PVC pipe, takes:Some trains brake with electromagnets held above the rails. The braking feels:Cutting slots in the swinging copper plate makes it:A copper plate swings between the poles of a magnet and soon stops. The cause is:A loop moves while lying fully inside a uniform magnetic field. The induced current is:Where does the work you do pushing the magnet into the coil end up?