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A copper rod of length $0.5$ m slides at $4$ m/s perpendicular to a $0.2$ T field. The motional EMF is:
A$1$ V, ignoring one of the three factors in the formula
B$0.4$ V, by $\varepsilon = Bvl = 0.2\cdot 4\cdot 0.5$
C$2$ V, multiplying field by velocity by velocity here
DZero, since the rod is not connected to anything
Answer & Solution
Correct answer: B. $0.4$ V, by $\varepsilon = Bvl = 0.2\cdot 4\cdot 0.5$
$\varepsilon = Bvl = 0.2\cdot 4\cdot 0.5 = 0.4$ V.
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