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Two parents who are both heterozygous carriers of sickle-cell anaemia (Hb^A Hb^S) plan a child. What is the probability that the child will be a homozygous affected individual?
AZero
BOne in two
COne in four
DThree in four
Answer & Solution
Correct answer: C. One in four
A cross Hb^A Hb^S x Hb^A Hb^S follows a 1:2:1 genotypic ratio. Homozygous Hb^S Hb^S, which expresses the disease, has a probability of one in four.
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