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The order of the differential equation obtained by eliminating the arbitrary constants $A$ and $B$ from $y = A e^{3x} + B e^{-3x}$ is:
A1
B2
C3
D4
Answer & Solution
Correct answer: B. 2
Two arbitrary constants ⇒ second-order DE. Indeed, differentiating twice and eliminating gives $d^2y/dx^2 = 9y$ — order 2.
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