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Euler's method for a DE y' = f(x, y) computes the next value as:
A$y_{n+1} = y_n + h f(x_n, y_{n+1})$ (implicit)
B$y_{n+1} = y_n \cdot f(x_n, y_n)$ (multiplicative)
C$y_{n+1} = y_n + h$ (no f)
D$y_{n+1} = y_n + h f(x_n, y_n)$ (explicit)
Answer & Solution
Correct answer: D. $y_{n+1} = y_n + h f(x_n, y_n)$ (explicit)
Euler's: explicit step using current slope. y_{n+1} = y_n + h × f(x_n, y_n). Simple but error O(h). RK4 is more accurate (averages 4 slope estimates, error O(h^4)).
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