45 g of ethylene glycol (M = 62) is dissolved in 600 g of water. K_f(water) = 1.86 K kg mol⁻¹. The depression in freezing point is approximately:
A1.5 K
B2.2 K
C0.5 K
D3.5 K
Answer & Solution
Correct answer: B. 2.2 K
Moles glycol = 45/62 ≈ 0.73 mol. Mass water = 0.60 kg. m = 0.73/0.60 ≈ 1.21 mol kg⁻¹. ΔT_f = 1.86 × 1.21 ≈ **2.2 K**.
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