How many real zeroes does p(x) = x² + 4 have?
A1
B2
C4
D0
Answer & Solution
Correct answer: D. 0
x² + 4 > 0 for every real x.
The parabola never crosses the x-axis.
D = 0 − 16 = −16 < 0, confirming no real zeroes.
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