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A solution of chloroform and acetone shows **negative deviation** from Raoult's law because:
AThey are immiscible
BTheir molar masses are different
CThey form an azeotrope at all compositions
DChloroform forms a hydrogen bond with acetone, strengthening A–B interaction relative to A–A and B–B
Answer & Solution
Correct answer: D. Chloroform forms a hydrogen bond with acetone, strengthening A–B interaction relative to A–A and B–B
CHCl₃ has a polar C–H that **H-bonds** with the lone pair on the C=O of acetone — A–B interactions are **stronger** than A–A or B–B → escape tendency drops → **negative deviation** (lower VP than predicted). Δ_mix H < 0.
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