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Raoult's law in its general form, for the solvent in a solution of a non-volatile solute, gives the relative lowering of vapour pressure as:
A(p₁⁰ − p₁)/p₁⁰ = x₂
B(p₁⁰ − p₁)/p₁⁰ = n₁/n₂
C(p₁⁰ − p₁)/p₁⁰ = x₁/x₂
D(p₁⁰ − p₁)/p₁⁰ = x₁
Answer & Solution
Correct answer: A. (p₁⁰ − p₁)/p₁⁰ = x₂
**Relative lowering of VP = mole fraction of solute (x₂)**. From Raoult's law: p₁ = x₁ p₁⁰; Δp/p⁰ = 1 − x₁ = x₂. This is a colligative property.
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