If sea water (density 1.03 g mL⁻¹) contains 5.8 g of dissolved O₂ per 10⁶ g of water, the concentration is best expressed as:
A5.8 M
B5.8% by mass
C5.8 ppm
D5.8 ppb
Answer & Solution
Correct answer: C. 5.8 ppm
Trace concentrations are expressed in **parts per million (ppm) = (mass of component / total mass) × 10⁶**. 5.8 g per 10⁶ g = **5.8 ppm**.
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