The molarity of a solution containing 5 g of NaOH (M = 40 g mol⁻¹) in 450 mL of solution is:
A0.111 M
B1.00 M
C0.500 M
D0.278 M
Answer & Solution
Correct answer: D. 0.278 M
Moles NaOH = 5/40 = 0.125 mol. Volume = 0.450 L. M = 0.125/0.450 = **0.278 M**.
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