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Five codebits a–e are0/1. a+b+c and b+c+d are even; c+d+e is odd. Received10110 has exactly2 wrong bits. Find the original first3 bits.

A110
B101
C011
D000
Answer & Solution
Correct answer: A. 110
The parity-valid codes00001,01100,10111,11010 differ from10110 in4,3,1,2 places, leaving11010, whose first3 bits are110.
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