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କୋଡ୍ ABCD ଭିନ୍ନ ସଂଖ୍ୟା 1–6 ବ୍ୟବହାର କରେ | C = 2D ଏବଂ A + C = B + D | ଦୁଇ ଅଙ୍କ ବିଶିଷ୍ଟ ସଂଖ୍ୟା AB ଏବଂ CD 24 ଦ୍ୱାରା ଭିନ୍ନ, AB ବଡ଼ ସହିତ | A × C + B × D ଖୋଜ |

A13
B11
C15
D17
Answer & Solution
Correct answer: A. 13
C=2D ବସାଇଲେ B=A+D। ତାପରେ AB−CD=11A−20D=24। D=1,2,3 ଏବଂ ଭିନ୍ନ 1–6 ଅଙ୍କ ପାଇଁ କେବଳ A=4,D=1 ସଠିକ୍। କୋଡ୍ 4521 ଓ A×C+B×D=8+5=13।
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