alleryWhich example disproves “All A are C” while satisfying “All A are B” and “Some B are C”?
AA={1}, B={1,2}, C={2}
BA={1}, B={1}, C={1}
CA={1,2}, B={1}, C={2}
DA={1}, B={2}, C={1}
Answer & Solution
Correct answer: A. A={1}, B={1,2}, C={2}
In B, A is contained in B and B overlaps C at2, but A’s member1 is outside C.
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