alleryत्रिज्या-7 cm उंचीचा सिलेंडर 10 cm वर एक जुळणारा गोलार्ध आहे. तळ वगळून क्षेत्र उघड? π = 22/7 वापरा.
A594 cm²
B902 cm²
C748 cm²
D1056 cm²
Answer & Solution
Correct answer: C. 748 cm²
फक्त सिलेंडरचे वक्र क्षेत्र आणि गोलार्धाचे वक्र क्षेत्र उघड आहे: 440 + 308 = 748 सेमी ².
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