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हें . दोन 3 m रुंद रस्ते मध्यभागांतल्यान वतात, 60 × 40 मी. फरसबंदी खर्च ₹20/m²?

A₹6180
B₹6000
C₹5640
D₹5820
Answer & Solution
Correct answer: D. ₹5820
हें . रस्त्यांचो आस्पाव 60 × 3 + 40 × 3 − 3 × 3 = 291 m² आसून ताचो खर्च 291 × 20 = ₹5820 आसा.
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