allery30 m by 20 m باغ کا احاطہ 216 m² کے ارد گرد ایک یکساں بیرونی راستہ۔ اس کی چوڑائی؟
A3 m
B1 m
C4 m
D2 m
Answer & Solution
Correct answer: D. 2 m
چوڑائی x کے لیے، (30 + 2x)(20 + 2x) − 600 = 216 دیتا ہے (x −2)(x + 27) = 0، تو x = 2 m۔
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