Start learning →

हें . 8 m उंचायेचो त्रिकोण क्षेत्रफळांत 12 m बाय 5 m प्लॉट इतलो आसता; ताचो आदार?

A7.5 m
B20 m
C30 m
D15 m
Answer & Solution
Correct answer: D. 15 m
हें . त्रिकोणाचो आदार 2 × (12 × 5) ÷ 8 = 15 मी.
Practise this question with Quill — RPF Constable →

Keep practising Mensuration

Browse all Mensuration questions for RPF Constable, or explore more Arithmetic topics.

Start a Mensuration lesson →