12 କିଲୋମିଟର / ଘଣ୍ଟାରେ ଜଣେ ସାଇକେଲ ଚାଳକ 2 ଘଣ୍ଟା ଅଗ୍ରଣୀ ପାଆନ୍ତି | ଘଣ୍ଟା ପ୍ରତି 18 କିଲୋମିଟରରେ ଏକ ବାଇକ୍ ଅନୁସରଣ କରେ | କ୍ୟାଚ୍ ଅପ୍ ସମୟ?
A3 ଘଣ୍ଟା |
B4 ଘଣ୍ଟା |
C6 ଘଣ୍ଟା |
D2 ଘଣ୍ଟା |
Answer & Solution
Correct answer: B. 4 ଘଣ୍ଟା |
ସାଇକେଲ ଚାଳକଙ୍କ ଆଗୁଆ ଦୂରତା 12 × 2 = 24 km ଏବଂ ବାଇକ୍ ପ୍ରତି ଘଣ୍ଟାରେ 18 − 12 = 6 km ବ୍ୟବଧାନ କମାଏ; ତେଣୁ 24 ÷ 6 = 4 ଘଣ୍ଟାରେ ଧରେ।
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