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बीजीय व्यंजक का विस्तार और सरलीकरण कीजिए: $(x + 3)(x - 3)$

Ax^2 - 9
Bx^2 - 6
Cx^2 + 9
Dx^2 - 3
Answer & Solution
Correct answer: A. x^2 - 9
$(x + 3)(x - 3) = x^2 - 3^2 = x^2 - 9$ (वर्गों के अंतर की सर्वसमिका)।
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