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In a club of 50 members, 28 play Chess, 24 play Carrom, and 8 play neither. How many play both games?

A10
B12
C14
D16
Answer & Solution
Correct answer: A. 10
Union = 50 - 8 = 42. Playing both = n(Chess) + n(Carrom) - Union = 28 + 24 - 42 = 10.
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