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If 'A' = 2, 'B' = 4, and 'C' = 6 (each letter's value is twice its alphabetical rank), what is the numerical value of 'CAB'?

A6
B8
C10
D12
Answer & Solution
Correct answer: D. 12
Letter values: C = 3*2 = 6, A = 1*2 = 2, B = 2*2 = 4. Total = 6 + 2 + 4 = 12.
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