8 से विभाजित करने पर, किसी विषम पूर्ण वर्ग द्वारा सदैव क्या शेषफल छोड़ा जाता है?
A3
B5
C1
D7
Answer & Solution
Correct answer: C. 1
प्रत्येक विषम संख्या 2k+1 के रूप की होती है। (2k+1)² = 4k² + 4k + 1 = 4k(k+1) + 1। चूंकि k(k+1) सदैव सम होता है, 4k(k+1), 8 का गुणज है। अतः सदैव 1 शेषफल बचता है।
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