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2 ꯅꯠꯠꯔꯒꯥ 5 ꯅꯠꯇꯕꯥ ꯄ꯭ꯔꯥꯏꯝ p ꯑꯃꯒꯤꯗꯃꯛ, 1/pꯒꯤ ꯗꯦꯁꯤꯃꯦꯜ ꯑꯦꯛꯁꯄꯥꯟꯁꯅꯒꯤ ꯄꯤꯔꯤꯌꯗ ꯂꯦꯡꯗꯅꯥ ꯂꯩꯕꯥ ꯑꯋꯥꯡꯕꯥ ꯕꯥꯎꯟꯗ ꯑꯗꯨ ꯀꯔꯤꯅꯣ?

Ap + 1
Bp / 2
C2p - 1
Dp - 1
Answer & Solution
Correct answer: D. p - 1
1/pꯒꯤ ꯍꯟꯖꯤꯟ ꯍꯟꯖꯤꯟ ꯇꯧꯕꯥ ꯗꯦꯁꯤꯃꯦꯜ ꯑꯦꯛꯁꯄꯥꯟꯁꯅꯒꯤ ꯄꯤꯔꯤꯌꯗ ꯂꯦꯡꯗꯅꯥ ꯂꯩꯕꯥ ꯑꯁꯤ ꯀꯩꯗꯧꯉꯩꯗꯥ p - 1ꯗꯒꯤ ꯍꯦꯜꯂꯣꯏꯗꯕꯅꯤ꯫
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