For a galvanic cell, $\Delta G^0$ of the cell reaction is −58 kJ/mol, with $n = 2$ electrons transferred. The standard cell EMF $E^0$ is approximately ($F = 96 485$ C/mol):
A1.20 V
B0.60 V
C0.15 V
D0.30 V
Answer & Solution
Correct answer: D. 0.30 V
$E^0 = -\Delta G^0/(nF) = 58 \times 10^3 / (2 \times 96485) \approx 0.30$ V.
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