A current of 2 A is passed through molten CuCl₂ for 30 minutes. The mass of copper deposited at the cathode is (atomic mass Cu = 63.5, $F$ = 96 485 C/mol):
A2.37 g
B4.74 g
C1.18 g
D9.48 g
Answer & Solution
Correct answer: C. 1.18 g
By Faraday's law: $m = (M \times I \times t)/(nF)$. Charge $Q = It = 2 \times 1800 = 3600$ C. Cu²⁺ + 2e⁻ → Cu so $n = 2$. $m = (63.5 \times 3600)/(2 \times 96485) \approx 1.18$ g.
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