A current of 2 A is passed through molten CuCl₂ for 30 minutes. The mass of copper deposited at the cathode is (atomic mass Cu = 63.5, $F$ = 96 485 C/mol):

By Faraday's law: $m = (M \times I \times t)/(nF)$. Charge $Q = It = 2 \times 1800 = 3600$ C. Cu²⁺ + 2e⁻ → Cu so $n = 2$. $m = (63.5 \times 3600)/(2 \times 96485) \approx 1.18$ g.