The molar conductivity of 0.01 M acetic acid is 16.5 Ω⁻¹ cm² mol⁻¹, and $\Lambda_0$ = 390.7 Ω⁻¹ cm² mol⁻¹. The degree of dissociation is approximately:
A0.042
B0.42
C0.0023
D0.95
Answer & Solution
Correct answer: A. 0.042
$\alpha = \Lambda_c / \Lambda_0 = 16.5 / 390.7 \approx 0.042$ — i.e. ~4.2% dissociation, consistent with acetic acid being a weak electrolyte.
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