Using Kohlrausch's law, if $\Lambda_0$(NaI) = 126.9, $\Lambda_0$(AgNO₃) = 133.4, $\Lambda_0$(NaNO₃) = 121.5 (all Ω⁻¹ cm² mol⁻¹), then $\Lambda_0$(AgI) equals:
A$138.8$
B$254.3$
C$381.8$
D$117.4$
Answer & Solution
Correct answer: A. $138.8$
$\Lambda_0$(AgI) = $\Lambda_0$(NaI) + $\Lambda_0$(AgNO₃) − $\Lambda_0$(NaNO₃) = 126.9 + 133.4 − 121.5 = **138.8** Ω⁻¹ cm² mol⁻¹ (NaNO₃ cancels Na⁺ + NO₃⁻).
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