How many digits will be in the square root of a perfect square with EXACTLY 8 digits?

**For a perfect square with n digits:** if n is even, its square root has n/2 digits if n is odd, its square root has (n+1)/2 digits. With n = 8 digits, the square root has 8/2 = 4 digits. **Example:** √10000000 = ~3162.27, so √(11,000,000+) is a 4-digit number the largest 8-digit perfect square is 99980001 = 9999², still a 4-digit root.