Home › MHT-CET › Physics › Electromagnetic Induction › A coil of 1000 turns and area $10\ \text{cm}^2$ …
A coil of 1000 turns and area $10\ \text{cm}^2$ rotates about an axis perpendicular to a uniform field $B = 0.02$ T at 50 rev/s. The maximum EMF induced is approximately:
A628 V
B0.63 V
C62.8 V
D6.28 V
Answer & Solution
Correct answer: D. 6.28 V
$\omega = 2\pi \times 50 = 100\pi$ rad/s. Peak EMF $= N A B \omega = 1000 \times (10\times10^{-4}) \times 0.02 \times 100\pi = 1000 \times 10^{-3} \times 0.02 \times 314.16 = 6.28$ V.
Related questions
When a rod moves perpendicular to a magnetic field at constant velocity, the FREE charges An LC circuit oscillates with angular frequency ω equal to:Maxwell's correction to Ampère's law introduced:A bar magnet is dropped through a vertical conducting ring. The magnet:A coil of inductance 0.5 H carries a current changing at 4 A s⁻¹. The induced EMF is:A magnetic flux through a coil changes from 4 Wb to 1 Wb in 0.3 s. The average EMF inducedEddy currents are reduced in transformer cores by:A transformer works on the principle of: