alleryStart learning →A Wien-bridge oscillator using identical R and C in the frequency-selective branch oscillates at frequency f₀ equal to which?
Af₀ = 1/(2π·R·C)
Bf₀ = R·C/(2π) only
Cf₀ = 1/(R+C) always
Df₀ = R·C² always
Answer & Solution
Correct answer: A. f₀ = 1/(2π·R·C)
Wien bridge: positive-feedback network passes f₀ = 1/(2πRC) with phase 0° and attenuation 1/3. Amp needs gain exactly 3 (Barkhausen) for sustained oscillation.
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