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A coil of 400 turns has each turn enclosing an area $A = (0.20\,\text{m})^2$. A uniform magnetic field perpendicular to the plane changes linearly from 0 to 0.50 T in 0.8 s. The magnitude of the induced EMF is:
A10 V
B25 V
C2.5 V
D5.0 V
Answer & Solution
Correct answer: A. 10 V
$|e| = N A \cdot (\Delta B / \Delta t) = 400 \times (0.20)^2 \times (0.50/0.8) = 400 \times 0.04 \times 0.625 = 10$ V.
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