A stone is dropped from rest. After 2 seconds its velocity is approximately:

1. Use v = u + gt with u = 0 (dropped from rest). 2. Take g = 9.8 m per second squared (downward) and t = 2 s. 3. v = 0 + 9.8 × 2. 4. v = 19.6 m per second. 5. Option B gives velocity after 1 s only; option D doubles unnecessarily. _Source: Selina Concise Physics ICSE Class 9, Ch 2 'Motion in One Dimension' (aplustopper.com extract)_