A couple consists of two equal and opposite forces of 4 N each, separated by 0.30 m. The moment of the couple is:

1. Moment of a couple equals one of the equal forces multiplied by the perpendicular separation between them. 2. Given F = 4 N and separation d = 0.30 m. 3. Moment = F × d = 4 × 0.30 = 1.2 Nm. 4. The sign depends on direction; the magnitude is 1.2 Nm. 5. Options A and C come from forgetting to multiply by 2 or doubling unnecessarily. _Source: Selina Concise Physics ICSE Class 10, Ch 1 'Force' (icsehelp.com chapter extract)_