A dissolved gas obeys Henry's law: $P = K_H x$. If the pressure above the solution is doubled while $K_H$ remains constant, the mole fraction of dissolved gas becomes
Ahalf of its original value
Bunchanged
Cdouble its original value
Dfour times its original value
Answer & Solution
Correct answer: C. double its original value
Since $x = P/K_H$, with $K_H$ constant at fixed temperature, doubling $P$ doubles $x$. Therefore the dissolved amount expressed as mole fraction becomes twice the original value.
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