For the pair a₁x+b₁y+c₁=0 and a₂x+b₂y+c₂=0, a unique solution exists when:
A$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq\dfrac{c_1}{c_2}$
B$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$
C$a_1=a_2$
D$\dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2}$
Answer & Solution
Correct answer: D. $\dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2}$
a₁/a₂ ≠ b₁/b₂ gives intersecting lines and a unique solution.
Keep practising Unit 2: Differentiation and Fundamental Derivative Rules
Browse all Unit 2: Differentiation and Fundamental Derivative Rules questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
$ in(180° - \theta)$ equals:A polynomial of degree 2 is called a:The common difference of the AP 3, 1, −1, −3, … is:If an AP has first term $a=6$ and common difference $d=-3$, which of the following is the The list $-1.0, -1.5, -2.0, -2.5, \ldots$ is an AP. What is its common difference?The square of any odd integer, when divided by 8, leaves remainderThe common difference of the AP 3, 1, −1, −3, … is:If the two lines are coincident (lie on top of each other), the pair has: