Integral ∫ 1/(1 + x²) dx =
A1/x
Barcsin(x)
Carctan(x) + C
Dln(1+x²)
Answer & Solution
Correct answer: C. arctan(x) + C
∫ dx/(1+x²) = arctan(x) + C. Standard integral.
Application in inverse trig substitution.
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Related questions
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